Matematika Sekolah Menengah Pertama Bantu jawab please poin lumayan mohon dijawab dengan benar:') mksh ya yng ush jawab dengan benar

Bantu jawab please poin lumayan mohon dijawab dengan benar:') mksh ya yng ush jawab dengan benar

No 1

bagian a :

= 3m² + 7m + 4

= ( 3m + 4 ) ( 1m + 1 )

= ( 3m + 4 ) ( m + 1 )

= ( m + 1 ) ( 3m + 4 )

bagian b :

= 2m² - 5m - 12

= ( 2m + 3 ) ( 1m - 4 )

= ( 2m + 3 ) ( m - 4 )

= ( m - 4 ) ( 2m + 3 )

bagian c :

= 6x² - 11x + 5

= ( 6x - 5 ) ( 1x + 1 )

= ( 6x - 5 ) ( x + 1 )

= ( x + 1 ) ( 6x - 5 )

No 2

[tex] = \frac{x {}^{2} - 5 {}^{2} }{x {}^{2} + 2x - 15 } [/tex]

[tex] = \frac{(x - 5)(x + 5)}{x {}^{2} + 2x - 15 } [/tex]

[tex] = \frac{(x - 5)(x + 5)}{(x - 3)(x + 5)} [/tex]

[tex] = \frac{(x + 5)(x - 5)}{(x + 5)(x - 3)} [/tex]

Jawaban :

[tex] = \frac{x - 5}{x - 3} [/tex]

No 3

[tex] = \frac{5ab}{12m} + \frac{7ab}{12m} - \frac{5ab}{12m} [/tex]

[tex] = \frac{5ab + 7ab - 5ab}{12m} [/tex]

= 7ab/12m

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